Python Institute PCEP-30-02 PCEP - Certified Entry-Level Python Programmer Exam Practice Test

One possible way to arrange the code boxes in the correct positions to form a conditional instruction which guarantees that a certain statement is executed when the speed variable is less than 50.0 is:

if speed < 50.0:

print("The speed is low.")

This code uses the if keyword to create a conditional statement that checks the value of the variable speed. If the value is less than 50.0, then the code will print “The speed is low.” to the screen. The print function is used to display the output. The code is indented to show the block of code that belongs to the if condition.

You can find more information about the if statement and the print function in Python in the following references:

• Python If … Else
• Python Print Function

The code snippet that you have sent is using the count method to count the number of occurrences of a value in a list. The code is as follows:

my_list = [1, 2, 3, 4, 5] print(my_list.count(1))

The code starts with creating a list called “my_list” that contains the numbers 1, 2, 3, 4, and 5. Then, it uses the print function to display the result of calling the count method on the list with the argument 1. The count method is used to return the number of times a value appears in a list. For example, my_list.count(1) returns 1, because 1 appears once in the list.

The expected output of the code is 1, because the code prints the number of occurrences of 1 in the list. Therefore, the correct answer is D. 1.

The code snippet that you have sent is trying to use the index method to find the position of a value in a list. The code is as follows:

the_list = [1, 2, 3, 4, 5] print(the_list.index(6))

The code starts with creating a list called “the_list” that contains the numbers 1, 2, 3, 4, and 5. Then, it tries to print the result of calling the index method on the list with the argument 6. The index method is used to return the first occurrence of a value in a list. For example, the_list.index(1) returns 0, because 1 is the first value in the list.

However, the code has a problem. The problem is that the value 6 is not present in the list, so the index method cannot find it. This will cause a ValueError exception, which is an error that occurs when a function or operation receives an argument that has the right type but an inappropriate value. The code does not handle the exception, and therefore it will terminate with an error message.

The expected result of the code is an unhandled exception, because the code tries to find a value that does not exist in the list. Therefore, the correct answer is C. The code raises an unhandled exception.

The code snippet that you have sent is calculating the value of a variable “total” based on the values in the range of 0 to 3. The code is as follows:

total = 0 for i in range(0, 3): if i % 2 == 0: total = total + 1 else: total = total + 2 print(total)

The code starts with assigning the value 0 to the variable “total”. Then, it enters a for loop that iterates over the values 0, 1, and 2 (the range function excludes the upper bound). Inside the loop, the code checks if the current value of “i” is even or odd using the modulo operator (%). If “i” is even, the code adds 1 to the value of “total”. If “i” is odd, the code adds 2 to the value of “total”. The loop ends when “i” reaches 3, and the code prints the final value of “total” to the screen.

The code outputs 2 to the screen, because the value of “total” changes as follows:

• When i = 0, total = 0 + 1 = 1
• When i = 1, total = 1 + 2 = 3
• When i = 2, total = 3 + 1 = 4
• When i = 3, the loop ends and total = 4 is printed

Therefore, the correct answer is B. The code outputs 2.

The code snippet that you have sent is a loop that checks if a variable “floor” is less than or equal to 0 and prints a string accordingly. The code is as follows:

floor = 5 while floor > 0: print(“+”) floor = floor - 1

The code starts with assigning the value 5 to the variable “floor”. Then, it enters a while loop that repeats as long as the condition “floor > 0” is true. Inside the loop, the code prints a “+” symbol to the screen, and then subtracts 1 from the value of “floor”. The loop ends when “floor” becomes 0 or negative, and the code exits.

The code outputs five “+” symbols to the screen, one for each iteration of the loop. Therefore, the correct answer is C. five.

Python is an interpreted programming language, which means that the source code is translated into executable code by an interpreter at runtime, rather than by a compiler beforehand. Interpreted languages are more flexible and portable than compiled languages, but they are also slower and less efficient. Assembly and machine languages are low-level languages that are directly executed by the hardware, while compiled languages are high-level languages that are translated into machine code by a compiler before execution.

The code snippet that you have sent is a conditional statement that checks if a variable “counter” is less than 0, greater than or equal to 42, or neither. The code is as follows:

if counter < 0: print(““) elif counter >= 42: print(”“) else: print(””)

The code starts with checking if the value of “counter” is less than 0. If yes, it prints a single asterisk () to the screen and exits the statement. If no, it checks if the value of “counter” is greater than or equal to 42. If yes, it prints three asterisks () to the screen and exits the statement. If no, it prints two asterisks () to the screen and exits the statement.

The expected output of the code depends on the value of “counter”. If the value of “counter” is 10, as shown in the image, the code will print two asterisks (**) to the screen, because 10 is neither less than 0 nor greater than or equal to 42. Therefore, the correct answer is C. * *